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Proof step 16 from proof enc-invert (previous step)

maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m, m - n0 ≤ maxenc(m)

User applied rule cut formula

And obtained the following new goals

Proof step 17:
maxenc(m) * (maxenc(m) + 1) = 2 * n0, m < n0 ⊦ (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m, m - n0 ≤ maxenc(m)
Proof step 19:
maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m, m < n0, m - n0 ≤ maxenc(m)

Rule argument

fma: m < n0

Additional information

Used formulas: m < n0