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Proof step 1 from proof fst-ls-01 (conclusion)

⊦ m.1 < m ↔ m ≠ 0 ∧ m ≠ 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m ≤ m.1 ⊦ m = 1, m = 0

Rule argument

Additional information

Used simplifier rules: fst-one: ⊦ 1.1 = 1;% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → n ≠ 0; (s)