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Proof step 3 from proof max-nls (previous step)

m < (maxenc(m) * maxenc(m) + maxenc(m)) / 2 ⊦ maxenc(m) * maxenc(m) + maxenc(m) = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ (maxenc(m) * (maxenc(m) + 1)) / 2 ≤ m ∧ m < ((maxenc(m) + 1) * (maxenc(m) + 2)) / 2

Rule argument

spec: <toplevel> name: max-size seq: ⊦ (maxenc(m) * (maxenc(m) + 1)) / 2 ≤ m ∧ m < ((maxenc(m) + 1) * (maxenc(m) + 2)) / 2 subst: [m] → [m]

Additional information

Used simplifier rules: ⊦ m * (n + 1) = m * n + m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult% ⊦ m < n → (n ≤ m ↔ false); (s) Used terms: m