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Proof step 26 from proof max-zero-01 (previous step)

m < 3 ⊦ m = 0, m = 1, m = 2

User applied rule constructor cut

And closed the goal!

Rule argument

var: m

Additional information

Used simplifier rules: nat freely generated by 0, +1;;% ⊦ m +1 = m + 1; (s)% ⊦ m + 1 ≠ 0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1; (ws)%n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0; (s)%n < n0 ⊦ m + (* n) < (* n0) ↔ m < n0 - n; (s)% ⊦ m ≠ 1 → (m < 2 ↔ m = 0); (s)