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Proof step 10 from proof add (previous step)

∀ m, n. m ^ (n + n1) = m ^ n * m ^ n1 ⊦ m ^ (n1 + n) = m ^ n * m ^ n1, m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ m + n = n + m
Proof step 12:
∀ m, n. m ^ (n + n1) = m ^ n * m ^ n1 ⊦ m ^ (n + n1) = m ^ n * m ^ n1, m = 0

Rule argument

spec: nat-basic name: c seq: ⊦ m + n = n + m subst: [n, m] → [n, n1] flags: <all paths>

Additional information

Used terms: n, n1