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Proof step 3 from proof inj-02 (previous step)

2^ n = 2^(m + 1) ↔ n = m + 1 ⊦ 2^ n = 2 * 2^ m ↔ n = m + 1

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: lemma-ax2 seq: ⊦ 2^(n + 1) = 2 * 2^ n subst: [n] → [m]

Additional information

Used simplifier rules: pot2-def: ⊦ 2^ m = 2 ^ m; Used terms: m