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Proof step 12 from proof lls-02 (previous step)

m < 2 ^ (m1 + 1), log2 m < m0, n < 2 ^ (m1 + 1), n < 2 ^ (m0 + 1), log2 m < m1, 2 ^ m1 ≤ m, n ≤ m, 2 ^ m0 ≤ n, 2 ^ m0 ≤ m, m0 ≤ m1 ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ 2^ m ≤ n ∧ n < 2^ m +1 → log2 n = m

Rule argument

spec: <toplevel> name: Log2def seq: ⊦ 2^ m ≤ n ∧ n < 2^ m +1 → log2 n = m subst: [m, n] → [m1, m] flags: <all paths>

Additional information

Used simplifier rules: pot2-def: ⊦ 2^ m = 2 ^ m;%pot2-def: ⊦ 2^ m = 2 ^ m;% ⊦ m +1 = m + 1; (s)% ⊦ ¬ n < n; (s) Used terms: m1, m