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Proof step 14 from proof lsucc-01 (previous step)

⊦ log2(2 * n + 1) = log2 n + 1, n = 0, 2 * n + 1 < 4 * 2 ^ log2 n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ m < n ↔ ¬ n ≤ m
Proof step 16:
4 * 2 ^ log2 n ≤ 2 * n + 1 ⊦ log2(2 * n + 1) = log2 n + 1, n = 0

Rule argument

spec: nat name: lels seq: ⊦ m < n ↔ ¬ n ≤ m subst: [n, m] → [4 * 2 ^ log2 n, 2 * n + 1] flags: <all paths>

Additional information

Used terms: 4 * 2 ^ log2 n, 2 * n + 1