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Proof step 7 from proof lsucc-01 (previous step)

⊦ log2(2 * n + 1) = log2 n + 1, n = 0, 2 ^ log2 n ≤ n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n < 2 ^ log2 n ⊦ log2(2 * n + 1) = log2 n + 1, n = 0

Rule argument

Additional information

Used simplifier rules: two-pot-zero: ⊦ 2 ^ n ≠ 0;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)