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Proof step 4 from proof lzer (previous step)

log2(m + 1) = 0, ∃ m0. 2^ m0 ≤ m + 1 ∧ m + 1 < 2^(m0 + 1) ⊦ m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
log2(m + 1) = 0, 2^ m0 < 2^(m0 + 1), m + 1 < 2^(m0 + 1), 2^ m0 ≤ m + 1 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: zero: ⊦ 2^ n ≠ 0;%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic