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Proof step 4 from proof pot-01 (previous step)

2^(n -1 + 1) = 2 * 2^ n -1 ⊦ 2 * 2^ n -1 = 2^ n, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
2 ^ ((n - 1) + 1) = 2 * 2 ^ (n - 1) ⊦ 2 * 2 ^ (n - 1) = 2 ^ n, n = 0

Rule argument

Additional information

Used simplifier rules: pot2-def: ⊦ 2^ m = 2 ^ m;% ⊦ n -1 = n - 1; (s)