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Proof step 2 from proof power-of-2-01 (previous step)

⊦ 4 * 2 ^ m / 2 * n = 2 * n * 2 ^ m, 2 ^ m = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ 4 * 2 ^ m / 2 = 2 * 2 ^ m, 2 ^ m = 1, n = 0

Rule argument

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ m * n = m * n0 ↔ m = 0 ∨ n = n0; (ws)