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Proof step 24 from proof cong-equiv (previous step)

n1 + m1 * m = m0 * m, n2 < m, m0 < m1, m0 * m < m1 * m ⊦ m * (m0 - m1) = n1, n1 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: rotate, discard

Additional information

Used simplifier rules: ⊦ ¬ m + n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic