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Proof step 3 from proof cong-equiv (previous step)

⊦ m | dist(n, n0) ↔ n % m = n0 % m, m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m ≤ n → dist(m, n) = n - m
Proof step 5:
⊦ m | dist(n, n0) ↔ n % m = n0 % m, m = 0, n ≤ n0
Proof step 26:
n ≤ n0 ⊦ m | n0 - n ↔ n % m = n0 % m, m = 0

Rule argument

spec: <toplevel> name: dist-fst seq: ⊦ m ≤ n → dist(m, n) = n - m subst: [n, m] → [n0, n] flags: <all paths>

Additional information

Used terms: n0, n