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Proof step 18 from proof divi-same (previous step)

m * n1 = dist(n0, m0) ⊦ m = 0, n2 = 0, m | dist(m * n2 + m0, n0), n0 ≤ m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
m * n1 = dist(n0, m0), m0 < n0 ⊦ m = 0, n2 = 0, m | dist(m * n2 + m0, n0)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)