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Proof step 21 from proof divi-same (previous step)

m * n1 = n0 - m0, m0 < n0 ⊦ m = 0, n2 = 0, m | dist(m * n2 + m0, n0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 22:
m * n1 = n3, n0 = n3 + m0, m0 < n0, m0 ≤ n0 ⊦ m = 0, n2 = 0, m | dist(m * n2 + m0, n0)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n0, m0, n]

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ m < n → ¬ n < m; (s)%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n0, m0, n