m * n2 + n3 = m * n1, n1 < n2 ⊦ m * (n1 - n2) = n3, n3 = 0
Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)