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Proof step 3 from proof gcd-add (previous step)

n ≤ m + n ⊦ gcd(n, m + n - n) = gcd(m, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ gcd(n, m) = gcd(m, n)

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m + n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n - m = n; (s)