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Proof step 1 from proof gcd-conq-one (conclusion)

gcd(m, n) = 1 ⊦ ∃ m0. n | dist(m * m0, 1)

User applied rule cut formula

And obtained the following new goals

Proof step 2:
gcd(m, n) = 1, n = 0 ⊦ ∃ m0. n | dist(m * m0, 1)
Proof step 4:
gcd(m, n) = 1 ⊦ n = 0, ∃ m0. n | dist(m * m0, 1)

Rule argument

fma: n = 0

Additional information

Used formulas: n = 0