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Proof step 10 from proof gcd-conq-one (previous step)

m * m0 = m1 * n + n0, gcd(m, n) = 1, n0 = 1, n0 < n ⊦ n = 0, n = 1, n | dist(m * m0, 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
m * m0 = m1 * n + 1, gcd(m, n) = 1 ⊦ n = 1, n = 0, n | dist(m * m0, 1)

Rule argument

Additional information

Used simplifier rules: ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1); (s)% ⊦ m < n → n ≠ 0; (s)