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Proof step 2 from proof gcd-div-01 (previous step)

n0 | gcd(m, n) ⊦ n0 | n

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: gcd-div-both seq: ⊦ n0 | gcd(m, n) → n0 | n ∧ n0 | m subst: [n0, m, n] → [n0, m, n]

Additional information

Used terms: n0, m, n