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Proof step 9 from proof gcd-div-one (previous step)

1 = dist(m * m0, n * n1), gcd(m, n) = 1, n0 = dist(n0 * m * m0, n0 * n * n1), ∃ n1. m * n1 = n * n0 ⊦ m | n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information