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Proof step 7 from proof gcd-le-both (previous step)

n ≤ m ⊦ m = 0, n = 0, gcd(m, n) ≤ m ∧ gcd(m, n) ≤ n

User applied rule cut formula

And obtained the following new goals

Proof step 8:
n ≤ m ⊦ m = 0, m = n, n = 0, gcd(m, n) ≤ m ∧ gcd(m, n) ≤ n

Rule argument

fma: m = n

Additional information

Used simplifier rules: gcd-id: ⊦ gcd(m, m) = m;%gcd-a: ⊦ gcd(m, gcd(n, n0)) = gcd(gcd(m, n), n0);% ⊦ m ≤ m; (s) Used formulas: m = n