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Proof step 3 from proof gcd-one (previous step)

gcd(m0, 1) = 1 ⊦ gcd(m0 + 1, 1) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: gcd-rec1 seq: ⊦ n ≤ m → gcd(m, n) = gcd(m - n, n) subst: [n, m] → [1, m0 + 1] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m + n - m = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ ¬ m + n < m; (s) Used terms: 1, m0 + 1