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Proof step 9 from proof gcd-trans (previous step)

n0 | n ⊦ gcd(m, n0) | gcd(m, n), gcd(m, n0) | n, gcd(m, n0) | n0

User applied rule insert lemma

And obtained the following new goals

Proof step 10:
⊦ gcd(m, n) | m
Proof step 11:
n0 | n, gcd(n0, m) | n0 ⊦ gcd(m, n0) | n0, gcd(m, n0) | n, gcd(m, n0) | gcd(m, n)

Rule argument

spec: <toplevel> name: gcd-divs seq: ⊦ gcd(m, n) | m subst: [m, n] → [n0, m]

Additional information

Used terms: n0, m