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Proof step 10 from proof gcd-zero-01 (previous step)

gcd(n, m) = 0, n < m ⊦ m = n

User applied rule apply lemma

And obtained the following new goals

Proof step 11:
m < n, gcd(m, n) = 0 ⊦ m = 0 ∧ n = 0

Rule argument

spec: <toplevel> name: gcd-zero-01-h seq: m < n, gcd(m, n) = 0 ⊦ m = 0 ∧ n = 0 subst: [m, n] → [n, m]

Additional information

Used simplifier rules: gcd-zero: ⊦ gcd(0, n) = n; Used terms: n, m