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Proof step 7 from proof gcd-zero-01 (previous step)

gcd(m, n) = 0 ⊦ m = n, m < n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
gcd(m, n) = 0, n < m ⊦ m = n

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≠ n → (m < n ↔ ¬ n < m); (ss)