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Proof step 3 from proof mod2 (previous step)

m % 2 = 0, prime(m) ⊦ m = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n))
Proof step 5:
prime(m), ∃ n0. m = n0 * 2 ⊦ 2 = 0, m = 2

Rule argument

spec: nat-div name: modex seq: ⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n)) subst: [n, m] → [2, m] flags: <all paths>

Additional information

Used terms: 2, m