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Proof step 2 from proof mult-01 (previous step)

n0 + 1 < n, prime(m * n) ⊦ m = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 + 1 < n, prime(m * n) ⊦ m = 1

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic