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Proof step 21 from proof ins-max (previous step)

max(x) < a0, ordered≤(a0 ' + x), ∀ a1. ins≤(a1, x) = x + a1 ' ∨ a1 < max(x) ⊦ a0 ' + x = x + a0 ', x = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a0

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ ordered≤(a ' + x) → ins≤(a, x) = a ' + x; (s)%transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem% ⊦ ¬ a < a; (s) Used terms: a0