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Proof step 12 from proof max-append (previous step)

max(x1 + x0) < a, ∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x0) ∨ max(x1 + x0) = max(x1) ⊦ x1 + x0 = [], a = max(x0), a = (max(x1) < a ⊃ a;max(x1)), x1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
max(x1 + x0) < a, ∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x0) ∨ max(x1 + x0) = max(x1) ⊦ x1 + x0 = [], a = (max(x1) < a ⊃ a;max(x1)), a = max(x0), x1 = []

Proof step 12 from proof max-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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