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Proof step 14 from proof max-append (previous step)

∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x0) ∨ max(x1 + x0) = max(x1) ⊦ x1 + x0 = [], (max(x1 + x0) < a ⊃ a;max(x1 + x0)) = max(x0), max(x1 + x0) = max(a ' + x1), max(x1 + x0) < a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x0) ∨ max(x1 + x0) = max(x1) ⊦ x1 + x0 = [], max(x1 + x0) = max(a ' + x1), max(x1 + x0) = max(x0), max(x1 + x0) < a

Proof step 14 from proof max-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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