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Proof step 2 from proof max-com-01 (previous step)

max(x + x0) < max(x0 + x) ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ x + x0 ≠ [] → (max(x + x0) = max(x0 + x) ↔ true)
Proof step 4:
max(x + x0) < max(x0 + x), x + x0 ≠ [] → (max(x + x0) = max(x0 + x) ↔ true) ⊦

Rule argument

spec: <toplevel> name: max-com seq: ⊦ x + x0 ≠ [] → (max(x + x0) = max(x0 + x) ↔ true) subst: [x, x0] → [x, x0]

Additional information

Used terms: x, x0