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Proof step 18 from proof max-ins-last (previous step)

max(x0) < a, a0 < a, ∀ a. max(x0) < a → ins≤(a, x0).last = a ⊦ (a0 ' + ins≤(a, x0)).last = a, ins≤(a, x0) = [], x0 = [], max(x0) < a0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
a0 < a, max(x0) < a, ∀ a. max(x0) < a → ins≤(a, x0).last = a ⊦ (a0 ' + ins≤(a, x0)).last = a, x0 = [], max(x0) < a0

Rule argument

Additional information

Used simplifier rules: ⊦ ins≤(a, x) ≠ []; (s)