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Proof step 5 from proof max-ins-max-last-sort (previous step)

⊦ ins≤(a, sort(x0)) = sort(x0) + a ', a < max(x0), ¬ a < max(sort(x0)) ∧ ordered≤(sort(x0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
a < max(sort(x0)), max(x0) < max(sort(x0)) ⊦ ins≤(a, sort(x0)) = sort(x0) + a ', a < max(x0)

Rule argument

Additional information

Used simplifier rules: nll: ⊦ ¬ b < a ∧ b < c → a < c; (forward) from specification oelem% ⊦ ordered≤(sort(x)); (s)