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Proof step 41 from proof max-ins-max (previous step)

ordered≤(a0 ' + x0), ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ (max(a0 ' + x0) < a ⊃ a;max(a0 ' + x0)) = a, a < max(a0 ' + x0), a0 < a, a0 < max(a0 ' + x0)

Heuristic cut applied rule cut formula

And closed the goal!

Rule argument

fma: max(a0 ' + x0) < a

Additional information

Used simplifier rules: ⊦ ¬ b < a → (a < b ↔ a ≠ b); (ss) Used formulas: max(a0 ' + x0) < a