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Proof step 29 from proof max-ordered (previous step)

max(x0) = a, a < max(x1), ordered≤(x0), x1 ⊑ x0 ⊦ max(x1) = a, x0 = [], x1 = [], max(x0) < a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
max(x0) < max(x1), ordered≤(x0), x1 ⊑ x0 ⊦ max(x1) = max(x0), x0 = [], x1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ a < a; (s)