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Proof step 2 from proof max-sort-sublist (previous step)

⊦ x + x0 = [], max(sort(x + x0)) = max(x), max(sort(x + x0)) = max(x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ x + x0 = [], max(x + x0) = max(x0), max(x + x0) = max(x)

Rule argument

Additional information

Used simplifier rules: sort-max-max-list: ⊦ x ≠ [] → max(sort(x)) = max(x);