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Proof step 2 from proof sort-max (previous step)

⊦ max(sort(x)) = sort(x).last, x = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ x ≠ [] ∧ ordered≤(x) → max(x) = x.last

Rule argument

spec: <toplevel> name: ordered-max seq: ⊦ x ≠ [] ∧ ordered≤(x) → max(x) = x.last subst: [x] → [sort(x)] flags: <all paths>

Additional information

Used simplifier rules: sort-max-max-list: ⊦ x ≠ [] → max(sort(x)) = max(x);% ⊦ sort(x) = [] ↔ x = []; (s)% ⊦ ordered≤(sort(x)); (s) Used terms: sort(x)