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Proof step 4 from proof app-01 (previous step)

ordered≤((a + x0) + y), ∀ y. ordered≤(x0 + y) → ordered≤(y) ⊦ ordered≤(y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
ordered≤((a ' + x0) + y), ordered≤(x0 + y), ∀ y. ordered≤(x0 + y) → ordered≤(y) ⊦ ordered≤(y)

Rule argument

Additional information

Used simplifier rules: cons-02: ⊦ ordered≤(a ' + x) → ordered≤(x);%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a + x = a ' + x; (s)