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Proof step 20 from proof del1-01-02 (previous step)

a < a0, ordered≤(a2 ' + y), ∀ a1, b. a1 = b ∨ ins≤(a1, (a2 ' + y) -1l b) = ins≤(a1, a2 ' + y) -1l b ⊦ a = a0, ins≤(a, a2 ' + y) = a ' + a2 ' + y, a2 < a0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: a2 < a

Additional information

Used simplifier rules: ins-n: ⊦ b < a → ins≤(a, b ' + x) = b + ins≤(a, x);%ins-y: ⊦ ¬ b < a → ins≤(a, b ' + x) = a + b + x;% ⊦ a + x = a ' + x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + y = x + z ↔ y = z; (s)%transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem%nll: ⊦ ¬ b < a ∧ b < c → a < c; (forward) from specification oelem Used formulas: a2 < a