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Proof step 4 from proof eq (previous step)

a ' = ins≤(a, y) ⊦ [] = y

User applied rule structural induction

And obtained the following new goals

Proof step 5:
a ' = ins≤(a, a0 + y0), ∀ a. a ' = ins≤(a, y0) → [] = y0 ⊦ [] = a0 + y0

Rule argument

indvar: y

Additional information

Used simplifier rules: list freely generated by [], +;;