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Proof step 5 from proof eqdef (previous step)

ordered≤(a ' + x0), ordered≤(y), perm(a ' + x0, y), ∀ y0. ordered≤(y0) ∧ perm(x0, y0) → x0 = y0 ⊦ a ' + x0 = y

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ perm(a ' + x, y) ↔ a ∈ y ∧ perm(x, y -1l a)
Proof step 7:
ordered≤(y), ordered≤(a ' + x0), perm(x0, y -1l a), a ∈ y, ∀ y0. ordered≤(y0) ∧ perm(x0, y0) → x0 = y0 ⊦ a ' + x0 = y

Rule argument

spec: list-perm name: del-01 seq: ⊦ perm(a ' + x, y) ↔ a ∈ y ∧ perm(x, y -1l a) subst: [y, x, a] → [y, x0, a] flags: <all paths>

Additional information

Used terms: y, x0, a