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Proof step 17 from proof ole-01 (previous step)

a0 < a, a1 < a, ∀ a3. ordered≤(ins≤(a3, a1 ' + y0)) ↔ ordered≤(a1 ' + y0) ⊦ ordered≤(a1 ' + ins≤(a, y0)) ↔ ordered≤(a1 ' + y0), a1 < a0

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a abort: F discard: T computed: F

Additional information

Used simplifier rules: ins-n: ⊦ b < a → ins≤(a, b ' + x) = b + ins≤(a, x);% ⊦ a + x = a ' + x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a