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Proof step 6 from proof ordered-append (previous step)

x0 = [], ordered≤(x0), ordered≤(a ' + x1), x0 ≠ [] → ¬ x0.head < (a ' + x1).last, ∀ x. ordered≤(x) ∧ (x1 ≠ [] ∧ x ≠ [] → ¬ x.head < x1.last) → ordered≤(x1 + x) ⊦ ordered≤((a ' + x1) + x0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-e: ⊦ ordered≤([]);%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + [] = x; (s)