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Proof step 28 from proof orderedle-all (previous step)

(a0 ' + y)[m0] < (a0 ' + y)[m2], ordered≤(a0 ' + y), m0 ≤ # y, m2 ≤ m0, m2 ≤ # y, ∀ m1, n. m1 ≤ n ∧ ¬ # y < n → ¬ (a0 ' + y)[n] < (a0 ' + y)[m1] ⊦ a0 < a

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: m2, m0

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: m2, m0