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Proof step 3 from proof sw (previous step)

⊦ ins≤(a, b ') = ins≤(b, a ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ b < a → ins≤(a, b ') = b ' + a '
Proof step 5:
⊦ ins≤(a, b ') = ins≤(b, a '), b < a

Rule argument

spec: <toplevel> name: ins-one seq: ⊦ b < a → ins≤(a, b ') = b ' + a ' subst: [b, a] → [b, a] flags: <all paths>

Additional information

Used simplifier rules: ins-one-02: ⊦ a < b → ins≤(a, b ') = a ' + b ';% ⊦ x + y = x + z ↔ y = z; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: b, a