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Proof step 3 from proof bmin-two-01 (previous step)

a < b ⊦ (∅ ++ a ++ b).butmin = ∅ ++ b

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 4:
a < b ⊦ (∅ ++ a ++ b).butmin = ∅ ++ b, b < a

Rule argument

fma: b < a

Additional information

Used simplifier rules: transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem% ⊦ ¬ a < a; (s) Used formulas: b < a