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Proof step 3 from proof max-del (previous step)

s.max < (s -- a).max ⊦ s = ∅ ++ a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ a ∈ s → ¬ s.max < a
Proof step 5:
s.max < (s -- a).max ⊦ s = ∅ ++ a, (s -- a).max ∈ s

Rule argument

spec: <toplevel> name: Max-max seq: ⊦ a ∈ s → ¬ s.max < a subst: [a, s] → [(s -- a).max, s] flags: <all paths>

Additional information

Used terms: (s -- a).max, s