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Proof step 4 from proof minmax-02 (previous step)

s.min = s.max, s.max ∈ s ⊦ # s = 1, # s = 0, s = ∅, s.min < s.max

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: minmax-03 seq: ⊦ 1 < # s → s.min < s.max subst: [s] → [s] flags: <all paths>

Additional information

Used simplifier rules: ⊦ 1 < m ↔ ¬(m = 0 ∨ m = 1); (s) Used terms: s